Yefim S. answered 01/15/22
Math Tutor with Experience
(a) About x-axis: V = π∫02(x3)2dx = πx7/702 = 128π/7
(b) x = 2, then y = 23 = 8; x = y1/3
V = π∫08(22 - y2/3)dy = π (4y - 3y5/3/5)08 = π(32 - 96/5) = 64π/5
(c) V = π∫08[(9 - y1/3)2 - 72]dy = π∫08(32 - 18y1/3 + y2/3)dy = π(32y - 27/2y4/3 + 3/5y5/3)08 =
π(256 - 216 + 96/5) = 296π/5