
Alyssa R.
asked 01/12/22Integral Question
Would anyone be able to help me solve this integral?
∫ (5x)^5 √(5x)^3 + 1 dx
1 Expert Answer

Yefim S. answered 01/12/22
Math Tutor with Experience
∫ (5x)^5 √(5x)^3 + 1 dx. y = 5x
∫ (5x)^5 √(5x)^3 + 1 dx = 1/5∫y5(y3 + 1)1/2dy = y3 + 1 = z; 3y2dy = dz; dy = dz/(3y2); z = (5x)3 + 1
= 1/15∫y5z1/2dz/y2 = 1/15∫y3z1/2dz = 1/15∫(z - 1)z1/2dz = 1/15(z3/2 - z1/2)dz = 1/15(2/5z5/2 - 2/3z3/2) + C =
2/75[(5x)3 + 1]5/2 - 1/45[(5x)3 + 1]3/2 + C
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Doug C.
Is the +1 under the radical or outside?01/12/22