Newton's Law of Cooling: T = (T0 - TA)e-kt + TA or T0 + TA(1 - e-kt)
The 1st part allows you to solve for k by pugging in T0=165 and TA= 70 T(t = 15) = 135
Rearranging the equation, you get (T-TA)/(T0-TA) = e-kt
Take the ln of both sides and rearranging, you get -1/t ln[(T-TA)/(T0-TA)] = k
How long to drop to 110 under the same conditions?
That's finding t knowing T's and k from previously. From the last equation, you can just switch k and t and plug in the new T to solve.