To find the rate of change of the function, you need the derivative:
d/dx(2log2x +8) = 4/(2x) where I have assumed that you meant natural log. If you actually meant log10, then you should transform the equation using log10x = lnx/ln(10) before you take the derivative.
Plug in 1 for x , i.e. evaluate f'(1) and multiply by 100 to get $/yr