Evaluate the logs!!

Question

Given log_b 2=1.276 and log_b 3=1.899, evaluate

a) log_b 12

b) log_b 4/3

c) log_b ³√3

Answer 1

a) log(b)12=log(b)(2*2*3)=log(b)2+log(b)2+log(b)3=1.276+1.276+1.899=4.451

 

b) log(b)(4/3)=log(b)(2*2/3)=log(b)(2*2)-log(b)3=log(b)2+log(b)2-log(b)3=1.276+1.276-1.899...

1.276+1.276-1.899=2.552-1.899=0.653

 

c) log(b)(3^[1/3])=(1/3)log(b)3=(1/3)(1.899)=1.899/3=0.633