Inactive Tutor answered 12/26/21
a)
Let B = (I-A)
B2=BB=(I-A)(I-A) = I - 2A + A2 = I-2A+A = I-A = B
b)
A2=A
AA=A
A=A-1A or A=AA-1
A=I
c)
Ax=λx
A2=A
A2-A=0
(A2-A)x=0
A2x-Ax=0
λ2x-λx=0
(λ2-λ)=0
λ(λ-1)=0
λ= 0,1
Muhammad A.
asked 12/26/21Let A be an idempotent matrix.
(a) Show that I − A is also idempotent.
(b) Show that if A is invertible, then A = I.
(c) Show that the only possible eigenvalues of A are 0 and 1. (Hint: Suppose x is an eigenvector with associated eigenvalue λ and then multiply x on the left by A twice.)
Inactive Tutor answered 12/26/21
a)
Let B = (I-A)
B2=BB=(I-A)(I-A) = I - 2A + A2 = I-2A+A = I-A = B
b)
A2=A
AA=A
A=A-1A or A=AA-1
A=I
c)
Ax=λx
A2=A
A2-A=0
(A2-A)x=0
A2x-Ax=0
λ2x-λx=0
(λ2-λ)=0
λ(λ-1)=0
λ= 0,1
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