
Bradford T. answered 12/26/21
Retired Engineer / Upper level math instructor
a)
Let B = (I-A)
B2=BB=(I-A)(I-A) = I - 2A + A2 = I-2A+A = I-A = B
b)
A2=A
AA=A
A=A-1A or A=AA-1
A=I
c)
Ax=λx
A2=A
A2-A=0
(A2-A)x=0
A2x-Ax=0
λ2x-λx=0
(λ2-λ)=0
λ(λ-1)=0
λ= 0,1