
Bradford T. answered 12/20/21
Retired Engineer / Upper level math instructor
(1+ex)ydy/dx = ex
Use separation of variables
∫ydy = ∫ex/(1+ex) dx
y2/2 = ln(1+ex) + C
At (0,1)
1/2 = ln(2) + C
C = 1/2 - ln(2)
y2/2 = ln(1+ex) -ln(2) + 1/2 = ln((1+ex)/2) + 1/2
y = ±√( 2ln((1+ex)/2) + 1)