Tom K. answered 12/20/21
Knowledgeable and Friendly Math and Statistics Tutor
The easiest way to show that the answer is no is to let each of x and y = 0 and evaluate.
When x = 0, we get -4y^2/2y^2 = -2 for all y not equal to 0, including as y goes to 0.
When y = 0, we get x^4/x^2 = x^2 for x not equal to 0, which has a limit of 0 as x goes to 0.
The two different limits, -2 and 0, tell us that there is no limit.