Sherwood P. answered 12/20/21
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Since y = f(x) is convex in the interval (-∞,0],
the limit of (y2 - y1) / (x2 - x1) > 0 for x1 < x2 < 0 as x1 → 0,
i.e., f'(x) < 0 in the limit as x → 0 from below.
Similarly, since y = f(x) is convex in the interval [0,∞),
the limit of (y2 - y1) / (x2 - x1) < 0 for x1 > x2 > 0 as x1 → 0.
i.e., f'(x) > 0 in the limit as x → 0 from above.
This means f'(0) is undefined, since the limit of (f(0+h)-f(0))/h is undefined as h → 0.