Yefim S. answered 12/16/21
Math Tutor with Experience
We know series tan-1t = x - t3/3 + t5/5 -t7/7 + t9/9 - ...;
tan-1t/t = 1 - t2/3 + t4/5 - t6/7 + t8/9 - . . .
∫0xtan-1t/tdt = (t - t3/9 + t5/25 - t7/49 + t9/81 - . . .)0x = x - x3/9 + x5/25 - x7/49 + x9/81 - ... =
∑0∞(-1)nx2n+ 1/(2n + 1)