LSAT test scores are normally distributed with a mean of 152 and a standard deviation of 5. What score would place you in the top 2% of test-takers? (Round your answer to the nearest whole number.)

Question

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LSAT test scores are normally distributed with a mean of 152 and a standard deviation of 5. What score would place you in the top 2% of test-takers? (Round your answer to the nearest whole number.)

Answer 1

use formula z = (x - mean)/SD, where x is the score, mean = 152 and SD = 5.

top 2% is the 98th percentile. find z corresponding to 98th percentile. It is 2.054.

use above formula to find x for 98th percentile:

2.054 = (x - 152)/5

5*2.054 + 152 = x

162.27 = x

x ~ 162