∫ (a=-3, b=A) (4 - x3) dx = (4x - x4/4) from -3 to A = (4A - A4/4) - (4*[-3] - [-3]4/4) =
4A - A4/4 - (-12 - 81/4) = 4A - A4/4 + (48/4 + 81/4) = 4A - A4/4 + 129/4
Stormee S.
asked • 11/30/21Evaluate the definite integral
Evaluate the definite integral where A > -3
∫(a=-3,b=A) (4-x^3)dx
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