
Yefim S. answered 11/30/21
Tutor
5
(20)
Math Tutor with Experience
Let x is side of box and y is height.
Then we have minimise function S = x2 + 4xy if V = x2y = 4; y = 4/x2;
S = x2 + 16/x; S' = 2x - 16/x2 = 0; 2x3 = 16; x3 = 8; x = 2 feet.
Now S'' = 2 + 32/x3 > 0 if x = 2. So, at x = 2 we have minimum.
x = 2 feet, y = 4/22 = 1 feet