Jason E. answered 11/30/21
Professional Math Tutor, 20+ years of experience
First let me apologize for the incomplete answer.
I have some thoughts
E[g(Zn)] = ∫g(Zn)fn(Zn)dZn,-∞, c-ε + ∫g(Zn)fn(Zn)dZn,c-ε,c+ε + ∫g(Zn)fn(Zn)dZn,c+ε, ∞
(The limits of integration follow each term)
I believe that when you now take the limit as n->∞ , you can show that the first and last terms approach 0. Also, fn(Zn)->1/(2ε) in the middle integral (I am unclear about how to bring the limit inside the integral, but I believe there is a theorem which can handle this.
Following this, I believe you can use the Law of Large Numbers
That's all I have for tonight. I will try to follow up later.
- Jason