Sidney P. answered • 11/28/21
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I think this is what is intended: ∫A5 (4 - 2x-3) dx = [4x + (-2)x-2/(-2)] = [4x + x-2]A5 = (20 + 1/25) - (4A + 1/A2) = 501/25 - 4A - A-2.
Stormee S.
also, how did you get [4x + (-2)x-2/(-2)] ?
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11/30/21
Sidney P.
The first is just formatting, using subscript and then superscript in the editor. As for the integration, you split it into two terms, with integral of 4 dx = 4x, and (-2) times integral of x^-3 = (-2) times x^-2 /(-2) by the rule integral x^n dx = x^(n+1) /(n+1).
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11/30/21
Stormee S.
yes thank you! how did you get the variables on ∫ to make it where it looks like everything was in the right spot?11/30/21