1 + i can be thought of as the vector from (0,0) to (1,1)
Draw a right triangle with vertices (0,0), (1,0), and (1,1)
A = distance from (0,0) to (1,1) = √[(1-0)2 + (1-0)2] = √2
B = C = angle of the triangle formed by the x-axis and the vector
= tan-1(1/1) = 45°
1 + i = √2(cos45° + i sin45°)