
Yefim S. answered 11/14/21
Math Tutor with Experience
tanθ =225/x; sec2θdθ/dx = - 225/x2; dθ/dx = - 225cos2θ/x2; dθ/dx = - [225x2/(x2 + 2252)]/x2.
dθ/dx = - 225/(x2 + 2252) = - 225/(2252 + 2822) = - 0.001729 rad/foot
Jayce V.
asked 11/14/21A building that is 225 feet tall casts a shadow of various lengths as the day goes by. An angle of elevation θ is formed by lines from the top and bottom of the building to the tip of the shadow, as seen in the figure above.
Find the rate of change of the angle of elevationdθdxwhen x=282.
θ'(282)= radians per foot. Round to five decimal places.
Yefim S. answered 11/14/21
Math Tutor with Experience
tanθ =225/x; sec2θdθ/dx = - 225/x2; dθ/dx = - 225cos2θ/x2; dθ/dx = - [225x2/(x2 + 2252)]/x2.
dθ/dx = - 225/(x2 + 2252) = - 225/(2252 + 2822) = - 0.001729 rad/foot
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