SA(x) = 6x2
dSA/dt = 12x·dx/dt = 5
dx/dt = 5/84 ft/hr
V(x) = x3
dV/dt = 3x2·dx/dt = 3·49·5/84 = 35/4 ft3/hr
Andrew Y.
asked 11/13/21A large block of ice in the shape of a cube is melting. All sides, x, of the cube melt at the same rate. At what rate is the volume of the block decreasing when x=7 if its surface area is decreasing at a rate of 5 ft2/hr ?
SA(x) = 6x2
dSA/dt = 12x·dx/dt = 5
dx/dt = 5/84 ft/hr
V(x) = x3
dV/dt = 3x2·dx/dt = 3·49·5/84 = 35/4 ft3/hr
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