One of the requirements for a subset of a vector space to be a subspace of the vector space is that the subspace must be closed under scalar multiplication. In other words, if v is in the subset then cv must also be in the subset (c is any real number).
W is not a subspace of lR2 because W is not closed under scalar multiplication.
For example, let v = (1/5, 1/6) and let c = √2. v is in W but cv is not.
Therefore, W is NOT a subspace of lR2.