Finding critical points

Question

Find critical points of 5.7x^2e^-0.5x and round to two decimal places

Answer 1

y=5.7x²e^-x/2

y' = -(5.7/2)x²e^-x/2+5.7(2x)e^-x/2 By the power rule

= 5.7xe^-x/2(-x/2+2)

Set y' to zero and solving for x to get the critical points

x = 0, 4