Antiderivatives Calculus

Question

Find the particular antiderivative that satisfies the following conditions:

dx/dt = 70/(√t); x(1) = 80

x =

Answer 1

x(t) = ∫70t^-1/2dt = 70(2)√t + C

x(1) = 80 = 140(1)+C

C=-80/140= -4/7

x(t) = 140√t - 4/7