Osman A. answered 11/08/21
Professor of Engineering Calculus and Business Calculus
Functions of Graphs
Let f(x) = ax + b/x. What are the critical points of f(x)?
f(x) = ax + b/x = ax + bx-1
f ' (x) = a – bx-2 = a – b/x2
For critical points: f ' (x) = 0 ==> a – b/x2 = 0 ==> a = b/x2 ==> x2 = b/a ==> x = ±√(b/a)
y = f(±√(b/a)) = a(±√(b/a)) + b/(±√(b/a)) = ±(a)√(b/a)) + ±(b)/√(b/a)) = ±√(ab) + ±√(ab) = ±2√(ab)
(x, y) = (±√(b/a), ±2√(ab))