Yefim S. answered 11/07/21
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f(x) = x3; f(2) =23 = 8; f'(x) = 3x2; f'(2) = 12;
Now linear approximation L(x) = 8 +12(x - 2); L(x) = 12x - 16
1.973 = f(1.97) ≈ L(1.97) = 12·1.97 - 16 = 7.64