Help me with Calculus

Question

Find the absolute maximum and minimum values of f on the given closed interval, and state where those values occur.

f(x)=(x-4)^3; (0,10)

Answer 1

Closed interval is [9, 10].

f'(x) = 3(x - 4)² = 0; x = 4;

f(0) = (0 - 4)³ = - 64 abs min

f(4) = (4 - 4)³ = 0

f(10) = (10 - 4)³ = 216 abs max