P = 300x - 60(x/25 + x^2/2000)
x = 4960
Harry C.
asked 11/07/21In a certain chemical manufacturing process, the daily weight y of defective chemical output depends on the total weight x of all output according to the empirical formula
y=0.04x+0.0005x^2
where x and y are in pounds. If the profit is $300 per pound of non-defective chemical produced and the loss is $60 per pound of defective chemical produced, how many pounds of chemical should be produced daily to maximize the total daily profit?
P = 300x - 60(x/25 + x^2/2000)
x = 4960
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