x2y = 2,592
y = 2,592/x2
Cost = 3·2·x2 + 2·4·xy
C(x) = 6x2 + 20,736/x ; x > 0
C'(x) = 12x - 20,736 / x2 = 0
12x3 - 20,736 = 0
x3 = 1728 ; x = 12 ; y = 18
Harry C.
asked 11/07/21A closed rectangular container with a square base is to have a volume of 2592 in^3. The material for the top and bottom of the container will cost 3 per in^2, and the material for the sides will cost 2 per in^2. Find the dimensions of the container of least cost.
Let x be the length of each edge of the base and y be the height.
x2y = 2,592
y = 2,592/x2
Cost = 3·2·x2 + 2·4·xy
C(x) = 6x2 + 20,736/x ; x > 0
C'(x) = 12x - 20,736 / x2 = 0
12x3 - 20,736 = 0
x3 = 1728 ; x = 12 ; y = 18
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