
Osman A. answered 11/05/21
Professor of Engineering Calculus and Business Calculus
Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)
f ''(x) = 24x3 − 15x2 + 8x
Detailed Solution:
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f'(x) = ∫f ''(x)dx = ∫(24x3 − 15x2 + 8x)dx = 24x4/4 − 15x3/3 + 8x2/2 + C = 6x4 − 5x3 + 4x2 + C
f(x) = ∫f'(x)dx = ∫(6x4 − 5x3 + 4x2 + C)dx = 6x5/5 − 5x4/4 + 4x3/3 + Cx + D
f(x) = (6/5)x5 − (5/4)x4 + (4/3)x3 + Cx + D