3x2-5y7 = 10
-5y7 = 10-3x2
divide both sides by -5
y7 = (3x2-10)/5
Get the seven root of both sides:
y = ((3x2-10)/5)1/7
Differentiate both sides of the original equation with respect to x.
6x - 35y6 (dy/dx) = 0
- 35y6 (dy/dx) = - 6x
dy/dx = 6x/ (35((3x2-10)/5)6/7) or (6/35)x/((3x2-10)/5)6/7