12x2 + 2y(dy/dx) = 7
dy/dx=(7-12x2)/2y
at (-2,4) dy/dx=(7-24)/8
the equation of the tangent line is -17/8 = (y-4)/(x+2)
Peter G.
asked 11/03/21Consider the equation 4x3+y2+2 = 7x
a) Use implicit differentiation to find dy/dx
b) Find the equation of the tangent line at ( -2 , 4)
12x2 + 2y(dy/dx) = 7
dy/dx=(7-12x2)/2y
at (-2,4) dy/dx=(7-24)/8
the equation of the tangent line is -17/8 = (y-4)/(x+2)
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