Inactive Tutor answered 11/01/21
Tutor
New to Wyzant
y = log(7x - 2)
y = log10(7x - 2)
Using the derivative rule:
AND the chain rule:
then dy/dx = 1/[(7x - 2)ln(10)]•7 = 7/[ln10(7x - 2)]
Jetro T.
asked 11/01/21Inactive Tutor answered 11/01/21
y = log(7x - 2)
y = log10(7x - 2)
Using the derivative rule:
AND the chain rule:
then dy/dx = 1/[(7x - 2)ln(10)]•7 = 7/[ln10(7x - 2)]
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