Yefim S. answered • 10/28/21
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h'(t) = 3sec2(3t+ 5); h''(t) =18sec(3t + 5)tan(3t+ 5)sec(3t + 5) = 18sec2(3t + 5)tan(3t + 5);
h''(3) = 18sec214tan14 = 6974.5
Daniel K.
asked • 10/28/21Let h ( t ) = tan ( 3 t + 5 ) . Find h' ' (3)
any help would be amazing
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Daniel K.
greatly appreciate it yefim very helpful10/29/21