Michael W. answered 03/12/15
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Steve,
The direct answer to your question is "yes, there's a way to convert one value to the other." It's a little bit off the beaten path, and I will admit that I'm not an expert on the exact technique, so this might not be the most efficient approach. But, it worked, so I figured I'd share, and others can refine the answer if there's a better way...
First, let's make sure we have the correct numbers for the result you got with the half-angle formula for sin(15). I get:
√((1-√3/2)/2)
So, the whole thing is under the square root, including the division by 2. So, if we split up the 2, it looks like this:
√(1/2 - √3/4)
The trick I know of for "de-nesting" a square root is to get the radical in this form:
√(a±2√b)
That doesn't quite look like what we have, but if you can write the expression under the radical as a±2√b, then there's a way to de-nest it.
We have:
√(1/2 - √3/4)
We need the coefficient of the √3 to be 2. So, we factor 1/8 out of 1/4, leaving 2. If you do the same thing to the 1/2 and factor out 1/8, that leaves 4. Sooooo, we've got:
√[(1/8)(4-2√3)] = √(1/8)*√(4-2√3)
We can leave the 1/8 thing for later, but now, we have the nested radical in the right pattern.
Ready for the trick?
- Find two numbers x & y such that they add up to "a" and multiply to "b."
- Make x the bigger of the two numbers.
- √(a-2√b) can be reduced to √x-√y.
In our problem, we've got √(4-2√3), so "a" is 4, and "b" is 3.
- x & y need to add to 4, and multiply to 3. 3 and 1 will do it.
- Make x the bigger of the two numbers. So, that's 3, and y is 1.
- √(4-2√3) is therefore equal to √x-√y, or √3 - √1. √1 is 1, so we get √3 - 1.
We still have to deal with the part that we factored out, which was √(1/8), which I think ends up being √2/4 after you rationalize it? So, the final answer is:
√2/4 * (√3 - 1)
Re-distribute the √2 to the expression inside the parentheses, and poof, I think that matches the answer you'd get using sin(180-15).
Hope this helps...