
Mark M. answered 10/26/21
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
220 = 200e5k
1.1 = e5k
ln 1.1 = 5k
Can you solve for k?
Jacob V.
asked 10/26/21(a) Find an expression for the number of bacteria after t hours. P(t)=
(b) Find the number of bacteria after 9 hours.
(c) Find the rate of growth after 9 hours.
(d) When will the population reach 4000?
Mark M. answered 10/26/21
Mathematics Teacher - NCLB Highly Qualified
220 = 200e5k
1.1 = e5k
ln 1.1 = 5k
Can you solve for k?
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