The slope of the normal (perpendicular) is the negative rec iprocal of the slope of the given line, in this case 2.
Therefore, the equation of the normal is 2=(y+2)/(x+5).
You should be able to put this form into the slope-intercept from.
T S.
asked • 10/25/21Math Question For Cal
What is the equation of the line in slope-intercept form through (-5,-2) and is perpendicular to 2x+4y=12
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