3x2+3y2(dy/dx)-9 (dy/dx)-9y=0
dy/dx=(94-3x2)/(3y2-9x) and at (2,4) dy/dx=4/5
The tangent is 4/5=(y-4)/(x-2)
Sandra H.
asked 10/24/213x2+3y2(dy/dx)-9 (dy/dx)-9y=0
dy/dx=(94-3x2)/(3y2-9x) and at (2,4) dy/dx=4/5
The tangent is 4/5=(y-4)/(x-2)
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