Bradford T. answered 10/24/21
Retired Engineer / Upper level math instructor
f(x) = 2x3-33x2+180x-10
f'(x) = 6x2-66x+180
Divide through by 6 and set to zero, then solve for x.
x2-11x+30 = 0
(x-5)(x-6) = 0
x = 5, 6
Smaller: 5
Larger: 6
Brandon G.
asked 10/24/21The function f(x) = 2x3 - 33x2 + 180x - 10 has two critical points. The smaller one equals _________ and the larger one equals ________
Smaller:
Larger:
Bradford T. answered 10/24/21
Retired Engineer / Upper level math instructor
f(x) = 2x3-33x2+180x-10
f'(x) = 6x2-66x+180
Divide through by 6 and set to zero, then solve for x.
x2-11x+30 = 0
(x-5)(x-6) = 0
x = 5, 6
Smaller: 5
Larger: 6
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