Qeer Q.

asked • 10/23/21

Discuss the continuity of g(x) at x=1

{ (1/x^2-x)+1/x, x<0

g(x)= { [[x-1]], 0<=x<=2

{ √x-2, x>2

1 Expert Answer

By:

Obaid J. answered • 10/23/21

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