\frac{2\left(a+b\right)}{a+b+c}\:\:a=1,\:b=2,\:c=3

Answer 1

Hello!

If I understood your question correctly, you need to put in the values given for A, B, and C and evaluate your expression--meaning do all the addition, multiplication and division until you have a fraction in its simplest form.

Key things to know are that you need to do the addition within the () before you multiply together the parts of the denominator.

So I think you're evaluating:

2/[(a+b)(a+b+c)] where a= 1, b=2, c=3

That gives you:

2/[(1+2)(1+2+3)]

Doing the addition first you have:

2/[(3)(6)]

Which after doing the multiplication in the denominator becomes:

2/[(18)]

After you do that, simplify the numerator and denominator by dividing out the common factor of 2.

1/[(9)]

Please see my video above, as I fully work the problem there and explain more about why we do things in the order shown.

Thanks!