Yefim S. answered 10/21/21
Math Tutor with Experience
a. Sabtructing equations we get: 4x - 6y = 0; 6y - 7z = 0; x = 3y/2; z = 6y/7. Substituting in last equation:
3y/2 + y + 48y/7 = K; 21y + 14y + 96y= 14K; y = 14K/131; x = 21K/131; z = 12K/131.
So, we have one parametr K
b) We have minimal positive integers solutions when K = 131, then x = 21, y = 14, z = 12