
Yefim S. answered 10/19/21
Math Tutor with Experience
Δy ≈ dy = y'(0)·Δx; y'(x) = 3cos3x; y'(0) = 3cos0 = 3; Δy ≈ 3·0.1 = 0.3;
Exact value Δy = sin0.3 - sin0 = sin0.3 = 0.29552
So, percent error ε = (03 - 0.29552)/0.29552·100% = 1.516%
Linda M.
asked 10/18/21Let y=sin(3x). If Δx=0.1 at x=0, use linear approximation to estimate ΔyΔy≈ dy = 0.3 Find the percentage errorerror = %
Yefim S. answered 10/19/21
Math Tutor with Experience
Δy ≈ dy = y'(0)·Δx; y'(x) = 3cos3x; y'(0) = 3cos0 = 3; Δy ≈ 3·0.1 = 0.3;
Exact value Δy = sin0.3 - sin0 = sin0.3 = 0.29552
So, percent error ε = (03 - 0.29552)/0.29552·100% = 1.516%
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