Yefim S. answered 10/15/21
Math Tutor with Experience
Let x is radius of cylinder. Then its height h = 12 - 3x/2. So, volume V = πx2(12 - 3x/2) = π(12x2 - 3x3/2).
V' = π(24x - 9x2/2) = 0; x = 0 or x = 16/3
V'' = π(24 - 9x); V''(0) = 24π > 0. So, at x = 0 we have min
V''(16/3) = - 24π < 0. So, if x = 16/3 cm we have maximum volume max V = π(16/3)2(12 - 3/2·16/3) =
1024π/9 cm3