Bradford T. answered 10/15/21
Retired Engineer / Upper level math instructor
Volume, B = ∫ab A(x) dx
Where A(x) is the area of the cross section.
Area of an equilateral triangle, A = (√3/4)s2, where s is the length of a side. A side is going to be
s=2√(196-x2). The base of B is a circle of radius of 14. Need to sum up all the triangle areas for x = -1 to 1.
A = (√3/4)(4)(196-x2) = √3(196-x2)
B = ∫-11√3(196-x2)dx = √3[196x-x3/3]-11 = √3(1174/3)