An ordinary (fair) die is a cube with the numbers 1 through 6. Imagine that such a die is rolled twice and the face values of the two rolls are added together. Event A: the sum is greater than 8.

Answer 1

Create a table of 2 die roll values (1-6) and the 36 possible sums of each

1 2 3 4 5 6

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

How many of those sums are greater than 8 (9, 10, 11, 12): there are 10

so probability of getting a sum of more than 8 is 10/36 = 5/18