Give the standard equation of the circle satisfying the given conditions.Center at the origin, contains (0,3)

Answer 1

Give the standard equation of the circle satisfying the given conditions.Center at the origin, contains (0,3)

The standard equation of a circle is:

(x - h)² + (y - k)² = r²

^where:

^{coordinates of center are (h,k)}

^{radius is r}

This circle has a center at (0,0) "Center at the origin"

The radius is 3. Point (0,3) is on the circle. This radius is on the x-axis and has length or 3.

The formula for this circle, in standard format, is:

(x - h)² + (y - k)² = r²

(x - 0)² + (y - 0)² = 3²

x² + y² = 9