ZOREH S. answered 10/19/21
The volume of the water is:
V = pi . r^2 . h Now get the derivative knowing that the radius of the base is fixed.
dV / dt = pi . r^2 . dh / dt = pi . 3^2 . (0.8) = 22.6 in^3/s
Gwen N.
asked 10/11/21A coffee pot in the form of a circular cylinder of radius 3 in. is being filled with water flowing at a constant rate. If the water level is rising at the rate of 0.8 in./s, what is the rate (in in3/s) at which water is flowing into the coffee pot? (Round your answer to one decimal place.)
ZOREH S. answered 10/19/21
The volume of the water is:
V = pi . r^2 . h Now get the derivative knowing that the radius of the base is fixed.
dV / dt = pi . r^2 . dh / dt = pi . 3^2 . (0.8) = 22.6 in^3/s
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