
Michael M. answered 10/08/21
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
Here we're relating the speed that car A is traveling, the speed that car b is traveling and the speed in which the distance between the cars is increasing.
So we're relating dA/dt, dB/dt and dD/dt where A is the distance traveled by car A, B is the distance traveled by car B and D is the distance between the cars.
Thus, we have to find a way to relate A, B, and D
Notice that these three distances form a right triangle.
A is the vertical side, B is the horizontal side and D is the hypotenuse.
Thus we can relate A, B, and D with the pythagorean theorem
A2 + B2 = D2
Now take the derivative with respect to t
2A*dA/dt + 2B * dB/dt = 2D * dD/dt
Lastly plug in the values
Get the distance that A and B traveled two hours after the start
Find how far they are apart from each other two hours after the start