
Jon S. answered 10/07/21
Patient and Knowledgeable Math and English Tutor
a
P(G1 and G2) = P(G1) * P(G2|G1)
P(G1) = 6/11
P(G2|G1) = 5/10 = 1/2
so P(G1 and G2) = 6/11 * 1/2 = 3/11
b
at least one green = 1 - probability no green
probability no green = 5/11 * 4/10 = 20/110 = 2/11
so probability at least 1 green = 1 - 2/11 = 9/11
c
P(G2 | G1) = 1/2 from above