1 Expert Answer
Bradford T. answered 10/06/21
Retired Engineer / Upper level math instructor
F(y) = y2-7y4(y+3y3)
To differentiate, you can either multiply out the expression and differentiate or use the product and chain rule.
F(y) = y2-7y5-21y7
F'(y) = 2y-35y4-147y6
--or--
F'(y) = 2y - 7y4(1+9y2) - 28y3(y+3y3)
= 2y-7y4-63y6-28y4-84y6
= 2y-(7+28)y4 -(63+84)y6
= 2y-35y4-147y6
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Meme T.
Differentiate10/06/21