
Arthur P. answered 10/07/21
Qualified Ivy League Tutor Specializing in Mathematics
I believe you are trying to determine continuity for f(x) = 3x-1 at x = 2.
Given ε = 0.5, then we have:
|x- 2| < δ → |(3x - 2) - 5| < ε
|(3x-2)- 5| = |3x - 7| < ε = 0.5
Multiply both sides by 2 to get:
|6x - 14| < 1
|6(x-2) - 2| < 1
|6(x-2) - 2| = |6(x-2)| - 2 < 1
|(x-2)| < 3/6 = 0.5
We have then that δ = 0.5 applies.
However, constant functions are always continuous, and f(x) = x is also continuous at all points (both are easily shown), so f(x) = 3x-2 is continuous at all points.