Find the slope of the tangent line to the graph of f(x)=x^2-5 at the point (3,4)

Answer 1

Slope of tangent to the graph of y = f(x) at the point (x, f(x)) is f'(x)

So, for the function f(x) = x² - 5, f'(x) = 2x.

At the point (3, 4), slope of tangent = f'(3) = 6.